Can anyone explain this "m" answer? Ans is -2,2,0,1

Question

What will be the output of the program? #include int main()
{
int i=-3, j=2, k=0, m;
m = ++i || ++j && ++k;
printf(“%d, %d, %d, %d\n”, i, j, k, m);
return 0;
}

Answer 1

Using || (logical or) you know that it is already true (=1) if the left side is true (different from zero).

As i = -3 it gets pre-incremented to i = -2.
Then the left side of the or-statement is -2, which is different from 0 and therefore true.
This is already enough to say, that the or returns true, so the right side is not evaluated at all (to save computation time). Therefore the values of j and k stay the same.

m is assigned 1 (=true), since the or expression returned true.

I hope it is clear now. Otherwise feel free to ask again, if my explanation was too confusing 😅

Answer 2

Yes, everything different from 0 is considered true.
And true is always converted to 1

j and k are not changed, because they are on the right side of the or-expression. But there is no need to compute it, since the left side is already true.

Basically the first two possible outcomes of
1 || 1 = 1
1 || 0 = 1
0 || 1 = 1
0 || 0 = 0

are simplified to
1 || ? = 1

It just does not matter what's there on the right.
So no need to compute anything, all on the right side is ignored, if the left side is already true.
j and k are on this ignored right side and therefore they won't change.

Answer 3

That was so clean and clear .Thank you so much mate
Appreciate it

Answer 4

Yes.

Because j and k is on the right side of the or expression.

Answer 5

So anything different from 1 or 0 is returned as true?
And why does the values of j and k don't get changed?