Need help with a loop

Question

Function loop(){
Static $a=1;
$b=1;
$a++;
$b++;

Return $a.$b;
}
For($i=0; $i<3; $i++)
Loop();
Echo loop();

The output is 52. I tried to understand why but i need help.

So the loop will be executed 2 times.
First output will be 22.
In the second one $a=2(because it is static) and $b=1.
So the output will be 21( from my humble knowledge)
Then the loop will stop because $i=3.

I am really confused. Thank you.

Answer 1

good day, razvan !
The $a variable is "static", so the first call of loop()
$a=2,$b=2
the 2-nd call of loop()
$a=3,$b=2
the 3-rd call of loop()
$a=4,$b=2
the 4-th call of loop()
$a=5,$b=2
and function returns 52

Answer 2

right..so every time when the loop starts $a will be equal to 1+ the last value of $a. Thank you Dmitriy!

Answer 3

:)) the question was why the output is 52. if somebody can explain me how php got this result. thank you

Answer 4

razvan , good luck!

Answer 5

The function loop() is executed 3 times in the for. The value for $a is 4 and $b is 2.
When you use echo the function loop() is executed one more time, and the value for $a change to 5

Answer 6

what are you tying to archive here?