What is the output of this code? int x = 1, y = 1, z = 1; cout << (++x || ++y && ++z); cout << x << y << z;

Question

I got this question in a quiz and I can't figure out in what order does the conditions are checked. Ans is 1211 why only X's value is changed?

Answer 1

Vedansh Mittal yes, answer should be 1211...

why :

there are two cout statements , out of which first one is to show boolean values... it might have answer 1 or 0 for first cout..

also note that if || (or operator) is there and first condition is passed, other part never gets evaluated... so, ++x is only evaluated and as ++x is not zero, cout prints 1.

++x made x as 2.

as only ++x is evaluated, y and z is still 1 and 1.

so, output is 1211..

Answer 2

Is the asnwer 1211 or 211? Of it is the former, I don't know. But if it is the latter, then it is because the compiler saw two options. It can increase x or it can increase both y and z.
Since there were no conditions to be satisfied, for it to choose one or the other, it chose to increase the first.

If the code was ++x && ++y && ++z, all would be increased.

Answer 3

ok..... well the answer is 1211 because there are two cout statements and the initial '1' is printed because if the first one

Answer 4

yeah... thanks to both of you