input elements into list then pop out duplicate elements into another list without using count function.

Question

in Python. (i used nested for loop but for big list it's not working )

Answer 1

Omar Faruk How would you tell which elements were removed?

Answer 2

Here is my solution based on your description, seems to be working:

https://code.sololearn.com/c3BWyxepYW76/?ref=app

Answer 3

a = [1, 2, 2, 3, 3, 3, 4]
from itertools import groupby
z, x = [], []
for q, w in groupby(a):
if len(list(w)) > 1: x.append(q)
else: z.append(q)
print(z, x)
#########################
z, x = [], []
[z.append(q) if len(list(w)) == 1 else x.append(q) for q, w in groupby(a)]
print(z, x)

Answer 4

Mert Yazıcı How would you tell what are the duplicate elements?

Answer 5

thank you and yes its working... 😍

Answer 6

with the help of Eduardo's code i made this code..Thank You Eduardo ☺️
https://code.sololearn.com/cqPV0mIR56dn/?ref=app

Answer 7

Check Out My Code Simple And Cute
https://code.sololearn.com/cqPV0mIR56dn/?ref=app

Answer 8

thank you MY.it's working ..i want to print removed elemnts too

Answer 9

in 2 line code

l=[1,2,3,4,4,3,4,5,7]
print(list(set(l)))

Answer 10

lis=[1,4,2,5,3,6,3,6,4,2]
f=set(lis)
for i in lis:
if i in lis:
lis.remove(i)
print("remove item:",lis)
print("After remove item:",list(f))