+ 2
Convert string as palindrome without any predefined methods
If string is jyo8j, need to insert o, y in 5,6 positions. And calculate no of insertions. Which can be done dynamically
2 odpowiedzi
+ 1
#include <iostream>
#include <stdlib.h>
using namespace std;
int main(){
   int n=0;
   string s;
   cout<<"Enter String: ";
   cin>>s;
   for(int k=s.length()-1,i=0 ; k>=0,i<s.length() ; --k,++i){
	  	if(s[k]==s[i]){
	  	    n++;	
		  }
	}  
	if(n==s.length()){
	  cout<<"Palindrome";
	}else{
		cout<<"not Palindrome";
	}
	 
  return 0;
}






