new regex question

Question

since my old question seemed to confuse a few of you(I'm terrible at wording things lol), here's a new one

I need a regular expression that will match any amount of zeros at the end of a number

yes, this is for the challenge

An example:

Number: 6768097
Trailing Zeros: 0

Number: 267700
Trailing Zeros: 2

number: 577880
Trailing Zeros: 1

You can send your full code, as I already have a code that produces the number that will be tested

Actually, I'll just include my code.

https://code.sololearn.com/Wm0CPovm9N4L/?ref=app

I saved it after experimenting a bit, so if you remove the zeros from the output it should work.

Answer 1

To match everything before the zeroes, you can express it like

([0-9]+[1-9])

Which means, a number, but at the end a digit that's not 0. Then you match all the zeroes after. We also need to consider the case when the number is all zeroes. The full regex then is:

([0-9]+[1-9])?(0*)

And in group 2 you have the trailing zeroes.

EDIT: Though, looking at Anna's answer on the last post, /0+$/ or /0*$/ is perfect if you know that the number is at the end of the line. Nothing wrong with that!

Answer 2

Can I have an example of that in my code Schindlabua?

Answer 3

Also, the number of zeros at the end is NOT known
The program takes all of the digits in the array and multiplies them. I want it to count the trailing zeros and display them. But i'm terrible at regular expressions xD

Answer 4

Jay Matthews Well what's a good way to achieve this?