In "printf", if i use "%f" it was working. But when i used "%d" it was not working. Why? I'm so beginner . Don't mind ! -_-

Question

include <stdio.h>

int main() {
int a,b;
float c;
scanf("%d %d %f",&a,&b,&c);
printf ("%d",a+b+c);

return 0;
}

Answer 1

If you want to print it as integer, you need explicit type cast:

printf("%d", (int) (a+b+c));

Answer 2

So, basically, C automatically converts your values to a float type. Because of the difference in their structure (representation in memory) you need to specify the right type in your template string (%f - for float in your case)