The question is to print all the Pythagorean triplet from a accepted range.I am getting repetitive values ex:3,4 and 4,3.

Question

import math
a=int(input("start range"))
b=int(input("end range"))
for c in range(a,b+1):
for d in range(a,b+1):
for l in range(a,b+1):
p=c**2+d**2
if l==math.sqrt(p):
print (c,d,l)
this is the code I wrote. I am getting the answer but I get repetative values ex3,4 ,5and 4,3,5. I only need 3,4,5 or 4,3,5 .how to I print without repetition. please just correct my mistake I don't want a new logic to solve this problem. I am relatively new to Python

Answer 1

thanks a lot for the answers

Answer 2

Hi shivaani!

As per your request, here's the smallest amount of change that'd fix your code: Modify line 5 to

for d in range(c,b+1):

This ensures that the second number in the Pythagorean triplet is no less than the first, thus removing duplicates.

Hope that helps 😊

Answer 3

Jay Matthews, the OP didn't want a different algorithm.

Answer 4

here's it, ask if you have any question😃
https://code.sololearn.com/caTIqKpqdXSR