Increments Operator Precedence

Question

int x = 10, y = 10;
x = x++ * ++x;
y = ++y * y++;
System.out.println(x + " " + y);

Output:
120 121

Why?

Answer 1

x = x++ * ++x
well x++ first takes the value of x(10) and then adds 1 x=11

so now we have 10 * ++x and we added 1 to x's value x=11 now

then ++x first adds 1 to the current calue of x(11) to be 12

and then it multiplies
so it does 10 * 12 = 120

++y * y++ does this
add 1 to that value y(10) to be y(11)

so we have 11 * y++ now and y=11

then we do y++ which first takes y's value (11) and then adds one y(12)

so the function will do 11 * 11
and output 121

Answer 2

It's simple.
prefix(++x) increments first, then assigns and suffix(x++) assigns or calculates first them increments. See, lessonhttps://www.sololearn.com/learn/JavaScript/1130/
If you still not get:
For x, x++ increments after multiplication, and ++x increments before multiplication. so, first term would be 10 and second would be 12.
Similarly for y, ++y increments before multiplication and y++ increments after multiplication. So, first term would be 11 and second also.

Answer 3

y = ++y * ++y
will output 132

Answer 4

Roel is there any way to increment both numbers first?

y = (++y) * (y++); // Outputs 121

Answer 5

if you mean something like this
you want to y = 11 * 12
you could do
int y = 10
y = ++y * ++y;
since they first increase and then take the value of y
also I'd recommend you trying a lot with increments to get to know then better

Answer 6

in the first equation our initial value of x is 10 ...

during x++ it first uses value of x as 10 and then it add 1 to it, thus now x value is 11 which when used as ++x , first 1 is added to the value of x (that was 11) and then used as 12...

so, x=x++*++x
=10*12=120

in the second one,
initial value of y is 10 which when used as ++y
first gets increased by 1 and then the value is put as 11.. after that it is y++ which means that first the value stored in y(that was 11) is used and then it is increased..

so, y=++y*y++
=11*11=121

Hope it helps you...

^_^