Can some one help me solve this random generator with peak values in between

Question

package com.suneel.tools;

import java.util.Random;
import java.util.Timer;
import java.util.TimerTask;

public class Submitresp extends Main {
public static Timer timert = new Timer();
public static int timervalue = 0;
public static int prevValue;

public static void main(String[] args) {
timert.scheduleAtFixedRate(timervalueIncrementer, 2, 2);
while (prevValue < 4) {

System.out.println(getSubmitresp(5, 9, 300, 700));
}
}

public static TimerTask timervalueIncrementer =
new TimerTask() {

@Override
public void run() {
timervalue = timervalue + 1;
}
};

// discrete value provider
/*
* min : low response min limit
* max : low response max limit
* lmax : max response min limit
* lmin : max response max limit
*/
public static long getSubmitresp(int min, int max, int lmin, int lmax) {
if (timervalue != prevValue) {
prevValue++;
return getRandomMaxResp(lmin, lmax);
} else {
return getRandomLowResp(min, max);
}
}

// random value generators
private static int getRandomLowResp(int min, int max) {
if (min >= max) {
throw new IllegalArgumentException("max must be greater than min");
}
Random r = new Random();
return r.nextInt((max - min) + 1) + min;
}

private static int getRandomMaxResp(int min, int max) {
if (min >= max) {
throw new IllegalArgumentException("max must be greater than min");
}
Random r = new Random();
return r.nextInt((max - min) + 1) + min;
}
}

Answer 1

Not complete code

Answer 2

completed the task. now can see the random low numbers and peak values will be triggered when timertask calls.

Answer 3

Thank you Daniel, can review this once and post if you can improve it better