Divisors

Question

So a friend of mine proposed a challenge to find all divisors for each number from 1 to 100

I did this, but I want to exclude the number itself from the list of divisors.

so for an example l, lets use 6
I want it to display 1, 2 and 3, but not 6.

How can I do this?

I've tried everything I can think of
https://code.sololearn.com/crgVG3IEEMDI/?ref=app

Answer 1

I agree with the answer above.
2. Option:
When you think about divisors- what is the biggest divisor of any number (apart from itself)?
It's half of the number, right?

So you can also write your inner for loop like this:

for(int u=1; u<=i/2; u++)

Answer 2

There are other ways, but this should work too: replace lines 9-15 by

if(u == i) {
cout << endl;
cout << endl; // >:)
}
else if(i%u == 0) {
cout << u << " ";
}

Answer 3

Just put a line break in front of Number:

Answer 4

So I implemented your solution dρlυѕρlυѕ

now the first iteration doesn't include a line break.

Answer 5

dρlυѕρlυѕ welp that solution was simple and obvious. Lol. Thanks.

Answer 6

Don't mention it. 👍