Prefix vs Postfix.. This is probably asked already but I can't really find my question.

Question

How is it that this code generates the same values? If prefix increments i before? In my head this is happening: i(0); i < 10; ++i means i is now 1: commence loop. So the position of i should be 1? I did read about the compiler making a temporary copy of i and using that temp value while it changed the actual value. IS THIS WHY?
for (int i = 0; i < 10; i++) {
postFix[i] = i;
}

for (int i = 0; i < 10; ++i) {
preFix[i] = i;
}

Answer 1

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Answer 2

Sounds good. Didn't know.

Answer 3

Not following