function that creates and returns a 2d array wont work

Question

this is the error im getting(as a note playground\:25:20 continues for every definition of the array):

..\Playground\: In member function 'float* geometry::cube(float, float, float, float, float, float)':
..\Playground\:23:41: error: cannot convert 'float (*)[3]' to 'float' in initialization
float _cube = new float[8][3];
^
..\Playground\:25:20: error: invalid types 'float[int]' for array subscript
_cube[0] = {x, y, z};

and the code:

float *cube(float x, float y, float z, float w, float h, float d){
float _cube = new float[8][3]; //i guess the error happens here the rest of the errors are because this didnt work in the first place

_cube[0] = {x, y, z};
_cube[1] = {w, y, z};
_cube[2] = {x, h, z};
_cube[3] = {w, h, z};
_cube[4] = {x, y, d};
_cube[5] = {w, y, d};
_cube[6] = {x, h, d};
_cube[7] = {w, h, d};

return _cube;
}

as an example here is code that works:

int *Point(int x, int y, int z){

int *_point = new int[3];

_point[0] = x;
_point[1] = y;
_point[2] = z;

return _point;
}

in the main function i want to be able to do

float *cube1 = cube(1, 2, 3, 4, 5, 6);
then access
cube1[0][0];
which would return 1
sorry if this is to much to read i just think all the info i presented is atleast somewhat necessary.

Answer 1

Its 2d so it needs tobe double pointer.
float**cube=new float*[row];

Then on each row
cube[0]=new float[3]; //row 0

You can use loop to make this easier

Answer 2

Its double pointer, simple explaination one * for one dimension 😄

Answer 3

Taste i see so more dimensions need more pointers

Answer 4

Thank you Taste but why do i need 2 "*"?