I want to append common elements of two lists into a new list and print all elements of two lists in new list without repetition

Question

l=[1,2,3,4]
m=[2,3,4,56,7]
z=[]
for i in l:
if i in m:
z.append(m[i])
print(z)

the elements 2,3,4 should be present in list z but it does not work .

and a new list say y=[] must be created which has all elements of I and y with out repeating the elements

Answer 1

Yes Diego Acero is correct. This can also be done as :
l=[1,2,3,4]
m=[2,3,4,56,7]
z=[]
for i in l:
if i in m:
z.append(i)
print(z)

Answer 2

You can try this way :
First extract element from list l. Then extract element from list m and then compare the first element of l with all elements of m. Then same with second, third and so on.
This may help :
l=[1,2,3,4]
m=[2,3,4,56,7]
z=[]
for i in l:
for j in m:
if i==j:
z.append(i)
print(z)

Answer 3

shivaani
You almost got it! Try changing line 6 for this:
z.append(i)

Answer 4

l = [1, 2, 3, 4]
m = [2, 3, 4, 56, 7]

# common elements
z = list(set(l) & set(m))
print(z) # [2, 3, 4]

# all elements without repetition
y = list(set(l) | set(m))
print(y) # [1, 2, 3, 4, 7, 56]