Kindly explain second cout statement..how n[i]=i+100 and n[j] works

Question

#include <iostream>
#include<iomanip>
using namespace std;
using std::setw;

int main()
{ int i,j;
int n[10];
for(i=0;i<10;i++)
{
n[i]=i+100;
}

cout<<"element"<<setw(10)<<"value"<<endl;
for(j=0;j<10;j++)
{
cout<<setw(5)<<j<<setw(10)<<n[j]<<endl;

}

return 0;
}

Answer 1

`n[i] = i+100;` gets assigned 10 times to an expression inside a loop like this

i = 0, n[0] = 0+100;
i = 1, n[1] = 1+100;
i = 2, n[2] = 2+100;
i = 3, n[3] = 3+100;
i = 4, n[4] = 4+100;
i = 5, n[5] = 5+100;
i = 6, n[6] = 6+100;
i = 7, n[7] = 7+100;
i = 8, n[8] = 8+100;
i = 9, n[9] = 9+100;

`cout << n[j] << endl;` prints out the values inside the array using another loop like so

j = 0, n[0] == 100, print out 100
j = 1, n[1] == 101, print out 101
j = 2, n[2] == 102, print out 102
j = 3, n[3] == 103, print out 103
j = 4, n[4] == 104, print out 104
j = 5, n[5] == 105, print out 105
j = 6, n[6] == 106, print out 106
j = 7, n[7] == 107, print out 107
j = 8, n[8] == 108, print out 108
j = 9, n[9] == 109, print out 109

Answer 2

Its realy appreciable effort from c++ soldier...
Thanks alot sir....