Trying to work out the Vowel challenge in Python 3

Question

I am trying to figure out how to print the number of each vowel either using a list(which did not work for me) or creating a count for each vowel (not exactly DRY, I know)

So far this is the most updated version of my code and is throwing back indentation errors towards the print statement, showing a as a non existant variable:

inp = input("Input: ")

acount = 0
ecount = 0
icount = 0
ocount = 0
ucount = 0

if "a" in inp:
a = acount + 1
if "e" in inp:
e = ecount + 1
if "i" in inp:
i = icount + 1
if "o" in inp:
o = ocount + 1
if "u" in inp:
u = ucount + 1

print("A: " + a + "\nE:" + e +"\nI: " + i + "\nO: " + o + "\nU: " + u)

Answer 1

i = input("Input: ")
print(i + "\n")
i = i.lower()
c = [0, 0, 0, 0, 0]
v = "aeiou"

for l in i:
if "a" == l:
c[0] += 1
if "e" == l:
c[1] += 1
if "i" in l:
c[2] += 1
if "o" == l:
c[3] += 1
if "u" == l:
c[4] += 1

print("A = ", c[0], "\nE = ", c[1], "\nI = ", c[2], "\nO = ", c[3], "\nU = ", c[4])

I managed to get the program to work, but am still interested if I could only use the variables v and c instead of individually listing letters. Thank you for the help