+ 10
Python programming question n.1
confusion={} confusion[1]=1 confusion['1']=2 confusion[1]+=1 sum=0 for k in confusion: sum+=confusion[k] print(sum) What does k mean in this program and why is the answer 4? Thank you 🌸
7 odpowiedzi
+ 15
Here a dictionary is created if name confusion
Second line-{1:1}
Third line-{1:1,'1':2}
Fourth line-{1:2,'1':2}
After that k refers to all the keys present in the dictionary I.e. 1,'1'
Hence, confusion[k] refers to all the values of the dictionary
So, it sums all the values of dictionary is 2+2=4
+ 3
Tyrant, the code is quite fine. Confusion is a dictionary here. (Although "sum" is not a very good variable name, as it's also a built-in function.)
+ 3
Thank you all ,especially Pulkit Kamboj,your explanation is very clear.
+ 2
I think you wrote the whole thing wrong...this is what i think you meant..
confusion={}
confusion.append(1)
confusion.append(2)
confusion[1]+=1
sum=0
for k in confusion:
sum+=k
print(sum)
K is a holder variable,it refers to a value in a container('confusion'),It keeps on changing till it reaches the end of the container...
All of this is covered in the python tutorial in the app....
+ 1
Thank you 🍰
Merry Christmas
0
a for loop is a control structure to iterate through things like = list, tuples, string, dicts, sets ... But not in integers ... In this case you built up a dicitionary which contains:
confusion = {
1: 2,
'1': 2,
}
# variable sum set to 0
sum = 0
And with the for loop:
for k in confusion:
sum += confusion[k]
# when you iterate through a dict
# you iterate on its keys, in this
# case 1 and '1' so when you say
# sum += confusion[k] is like:
# sum += confusion [1]
And the value of the key 1 is 2
# sum += confusion['1'
And the value of the key '1' is 2
# so the for loop will sum those values to the variable sum...
print(sum)
0
when you use for loop, all the numbers will be iterated through. And when you combine "sum=0" with numbers that are iterated together, it will gives you the number 4(0+1+2+1).That's what I think he he:))