Why we need to put const in front of array of string , dealing with enumeration. I want to convert from number enum to string

Question

Why we need to put const in front of array of string , dealing with enumeration. I want to convert from number enum to string . I mean this const string str[8]

#pragma once
#include <iostream>
using namespace std;
#include<string>
enum KOLONA { A, B, C, D, E, F, G, H };
const string str[8] = { "A","B","C" ,"D", "E", "F", "G", "H" };
class Polje
{
KOLONA kol;
int red ;

public:
Polje();
Polje(KOLONA koll,int redd) :kol(koll),red(redd) { }
friend bool operator==(const Polje& p1, const Polje& p2) {
return (p1.kol == p2.kol) & (p1.red == p2.red);
}
friend bool operator+ (const Polje& p1, const Polje &p2) {
return (p1.kol == p2.kol) || (p1.red == p2.red);
}
friend bool operator/(const Polje& p1, const Polje& p2) {
return (p1.kol-p2.kol)==(p1.red-p2.red) ;
}
const string getKol() { return str[kol]; }
int getRed() { return red; }
~Polje();
};

Answer 1

So you're saying it will fail the getKol() function if your string array wasn't constant? If so, what does the error say?