Can anyone tell me how is it printing '012' ?

Question

#include<stdio.h>

void fun(int n)
{
if(n>0)
{
fun(--n);
printf("%d",n);
}
}
int main()
{
int a=3;
fun(a);
return 0;
}

Answer 1

I do understand how is it happening
like when n becomes 0 after all the decrements
it return back to fun (1) and prints the the value of n which is 0
and after that it goes to fun (2) where it prints 1
and after that in fun(3) it prints 2
Then the compiler gets out of the function fun ()😁

Answer 2

#Rewa Mathur
I just wanted to know after n becomes 0
What happens next ?
Thanks by the way i got my answer

Answer 3

Gordie
I agree with you i need to see more deeply in the recursive functions

Answer 4

I just somehow forgot that the compiler will come back to printf after the decrementing processes are done