Regex: matching special characters lesson doubt.

Question

string: 1 + 3 * (2 + 2)+789
regex: 1 \+ 3 \* \(2 \+ 2\).
output: 1 + 3 * (2 + 2)+
that's the output the 'try yourself' is generating. why does the output stop at + and not print 789?

link to lesson: https://www.sololearn.com/learn/9795/?ref=app

Answer 1

You added a . to the regex, that's why the + is matched. If you want it to match 789 as well, add a * to the regex (or something like \d*, \d+, \d+\b etc.)

Answer 2

Anna Thank you!