C++ task about perfect number

Question

The task
Creat a program that imports 10 natural numbers from the keyboard and determines only the sum of the perfect numbers

#include <iostream>
using namespace std;

int main() {
int number, counter=1, sum=0, y=0, temp;
for (int i=0; i<10; i++)
cin>>number; // it is for importing 10 numbers
temp=number;
if(number<=0){
cout<<"error";
return 0;
}
while (counter<temp){ // if you want know
if((temp%counter)==0) // your number is
sum+=counter; // perfect or not you must
counter++; // divide it all the numbers that
} // smaller than it

if (number==sum){
y=y+number; }

else { break; }

}
cout<<y;
return 0;
}

The problem is that I don't know where is my mistake

Answer 1

https://code.sololearn.com/cpCcx5rU7gbp/?ref=app
Edin Hajdarevic Arsen

Answer 2

Mina kapa dole

Answer 3

Thanks Mina for helping

Answer 4

wait, what is the perfect number? also, please use code feature so it will be easier for us to fix the problem

Answer 5

For example 6
it have 4 divisors
1, 2, 3, and 6
If the sum of all divisors(of course except 6) is equal our number 6 it calls perfect number
Perfect numbers are 6, 28, 496, 8128 after that the numbers are too high
For example 28 . It divisors are 1, 2, 4, 7, 14;
1+2+4+7+14=28
It means that 28 is a perfect number

Answer 6

Is that what you want?

https://code.sololearn.com/cnpbjTi0TMXb/?ref=app

Answer 7

Edin no it is not right code . I think that it will be easier if you do it without arrays

Answer 8

And your code brings error

Answer 9

will try to find a solution tonight.

Answer 10

Thanks Edin

Answer 11

Mina user has to input number