Why my 2nd char input line in do_while loop getting skipped?

Question

Can anyone help? My 2nd char input line in do_while loop getting skipped . . . here's the code:
#include <stdio.h>
main()
{
char C,A;
printf("\n ASCII Converter\n");
do
{
printf("\n Enter the Char: ");
C=getchar();
printf(" ASCII CODE/VALUE: %d\n",C);
printf("Again? y/n\n\n");
scanf("%c",A);
}while (A=='y' || A=='Y');
if(A=='y' || A=='Y')
return 0;
}

Answer 1

scanf needs a reference.

scanf("%c", &A);

Answer 2

Try entering "cyan" (without the quotes) when submitting inputs.

Answer 3

Could you please put the code on Code Playground and put the link in this thread? It would be much easier to debug.

Answer 4

There is nothing wrong with this code. What's the problem?

scanf doesn't print anything if this is what you have in mind.

Answer 5

updated:
#include <stdio.h>
main()
{
char C,A;
printf("\n ASCII Converter\n");
do
{
printf("\n Enter the Char: ");
scanf("%c",&C);
printf(" ASCII CODE/VALUE: %d\n",C);
printf("Again? y/n\n\n");
scanf("%c",&A);
}while (A=='y' || A=='Y');
if(A=='y' || A=='Y')
return 0;
}

still not working :/

Answer 6

here: https://code.sololearn.com/c3Bi9CaN3OcF

Answer 7

the #12 line, where it should've taken an char input y or something else then repeat the loop, it doesn't. No matter what, I cant make the loop repeat.

Answer 8

getting somewhere now... ayby shows the value of a then y repeats the loop shows the value of b then y repeats the loop.