Is this code even correct?

Question

I don't understand what this code means which is often used in the tutorials from sololearn, but nowhere else:
int x = 1
int y = x++ //now in y stands 2
std:cout << ++y << endl

what us this ++ thing in cout? it makes no sense and I don't think it's good programming behaviors especially for beginners.

Answer 1

Line 'y=x++;' - y gets the value of x, so y is now 1, and then x++ increments the value of x, so now x=2
Line 'cout<<++y<<endl;' y gets incremented so y is now 2, and then it is printed

Answer 2

go back and do lesson 1:11 Basic Concepts. Assignment and Increment EDIT: They explain it very well.

Answer 3

ah yeah, so i got that correct. dont get me wrong,i work with C since 7 years, but i have never seen this kind of line with cout ... i was just wondering why they use it that way