"Double Loop" in shell.

Question

Hey guys I am trying to write a .sh file, looks like this:

#!/bin/sh

# simps.sh
#
for x in 10 100 1000 10000
do
for n in 11 101 1001 10**4 + 1 10**5 + 1 10**6 + 1 10**7 + 1
do
(./simps | tail -n 1) << !
$x
$n
!
!

done

** The idea is that I want it to call the .c code, provide the x value, and for that x value run the .c code with different n values.

Answer 1

And how is it behaving at the moment? I'm not too familiar with bash shell scripting. What are the ! 's doing? And what are the for loops supposed to be doing with that syntax? Will it loop through 0 to 10 then 0 to 100 etc ?

You also need to put 'done' after the inner loop as well.