What does built-in function type do in context of classes?

Question

Determines which name of any value

Answer 1

#include <stdio.h>

int main() {
int i,j,a[6]={'t','h','a','n','k','s'};
for(i=0;i<=5;i++)
{
for(j=0;j<=5;j++)
{
if(i==j)
printf("%c",a[j]);
else
printf ("*");
}
printf ("\n");
}
return 0;
}

Answer 2

T👍👍👍👍👍
👍H👍👍👍👍
👍👍A👍👍👍
👍👍👍N👍👍
👍👍👍👍K👍
👍👍👍👍👍S

Answer 3

If you give only 1 arg, it returns arg.__class__

In [1]: int.__class__
Out[1]: type

In [2]: type(int)
Out[2]: type

In [3]: i = 5

In [4]: i.__class__
Out[4]: int

In [5]: type(i)
Out[5]: int

If you give 3 args (name, bases, attrs), it creates a new type

In [10]: cls = type('name', (object,), {'a': 5})
#This is equivalent to
#class name(object):
# a = 5

In [11]: cls
Out[11]: __main__.name

In [12]: type(cls)
Out[12]: type

In [13]: type(cls())
Out[13]: __main__.name

In [14]: cls.a
Out[14]: 5

In [15]: cls().a
Out[15]: 5

Answer 4

I think you have already done it then post it😁

Answer 5

Type returns the type of whatever you hand over.

If you give an int, type will be 'int'.

if you give a self-made class itself, type will be 'type'.

if you give an instance of your class, you will get the name of that class, because that's the type.

You can try these things yourself in Code Playground.

Answer 6

Mert Yazıcı, interesting, I haven't seen this creative side of 'type' yet.

Looks a bit like JavaScript, doesn't it?

Answer 7

Now do that pattern with code!

😁