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How could I print specific lines of a code in console?
The following codes print "Your Source Code as Output". And, I know that instead of the macro FILE, you enter the path of your file. Let's say...I write a C/C++ code & wanna print from Line "x" to Line "y" or different lines of the same code in the output. How could I achieve that?! One final question: Why in the C code is it printed this character <�> 'question mark inside diamond' at the end? https://code.sololearn.com/c3iNofIQ55ok/?ref=app https://code.sololearn.com/cm1855fzWF5M/?ref=app
13 odpowiedzi
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C++ Soldier (Babak) Thanks for your explanation!!
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diego Code Reviewing your code, I see that the null character as Rowsej stated is not printed. Is it because of your explanation?!
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diego Code Rowsej Thanks for explaining & providing nice resolutions. Now, I can do what I want to. Thanks a lot!!!
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~ swim ~ Thanks for expanding the former replies!!!
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So, if I need different ranges, should I repeat the same process?!
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Rowsej Yep, I prefer that approach!
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"Why it doesn’t show in C++ is a mystery to me though"
Simple!
`std::string`, unlike C-string, is not a null-terminated object. As already pointed out, the `\0` character in a C-string object signals the end of the string because, in the implementation, there's no such thing as `str.length()` [it holds `content + '\0'`]. The '\0' is there to provide such effect, for example, when you call `strlen(str)` which reads the string until '\0' and returns the "visible length" of the string. The STL string container, however, holds `content + length` pretty much the same way that the `std::vector` does.
Note: Though, the traditional null-terminated buffer effect is achievable by a `c_str()` call.
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In the C code you are testing eof after printf.
In the C++ you sre testing before eof, so if eof is reached, exits loop before printing.
https://code.sololearn.com/cc1f605tK9bZ/?ref=app
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https://code.sololearn.com/ctqT5fI3CBJQ/?ref=app
The question mark thing is the null character (U+0000), and it signals the end of a string. Why it doesn’t show in C++ is a mystery to me though.
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Yes. Instead of using #define you could put them into variables, and put the whole thing into a function that could be called again and again.
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Your program , modified yo print s range of lines.
https://code.sololearn.com/cirOM2lr70zs/?ref=app
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Yes. I test eof before doing loop body. So It doesn't print garbage.
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You're welcome!! :)