function error

Question

hello guys i'm trying to resolve this, for a while but i couldn't
please healp
here's my source code:

#include <iostream>
using namespace std;

float fonction (float x , float y , char n);

{ ---------------------// error "Expected unqualified-id"
float sum;
switch ('n')

{
case '+' :
sum =x+y;
cout<<" le resultat de :"<<x<<"+"<<y<<" = "<<sum << endl;
break;

case '-' :
sum =x-y;
cout<<" le resultat de :"<<x<<"-"<<y<<" = "<<sum<< endl;
break;

case '*' :
sum =x*y;
cout<<" le resultat de :"<<x<<"*"<<y<<" = "<<sum<< endl;
break;

case '/' :
sum =x/y;
cout<<" le resultat de :"<<x<<"/"<<y<<" = "<<sum<< endl;
break;

default '+':
sum =x+y;
}

return sum;
}
int main(int argc, const char * argv[]) {
// insert code here...
float a=12;
float b=17;
float fonction (float a ,float b, char (n)) ;

return 0;
}

Answer 1

Akagami 👌☺️

Answer 2

switch('n') => switch(n)
Remove the semicolon in line 4
default '+' isn't possible. Either default: or case '+':
float fonction (float a ,float b, char (n)) in main() is another function declaration, not a function call. You don't call the function anywhere. It is called like this: fonction(a, b, c)

Answer 3

thank's a lot its much better like this :

#include <iostream>
using namespace std;

float fonction (float x , float y , char n)

{

float sum;
switch (n)

{
case '+' :
sum =x+y;
break;

case '-' :
sum =x-y;
break;

case '*' :
sum =x*y;
break;

case '/' :
sum =x/y;
break;

default:
sum =x+y;
}

return sum;
}
int main(int argc, const char * argv[]) {
// insert code here...
float fonction (float, float, char);
float a,b;
char n ;
cout<< "insert the values"<<endl;
cin>> a>>b;
cin>> n ;

cout<<" le resultat de :"<<a<<"+"<<b<<" = "<<fonction(a, b, '+')<< endl;
cout<<" le resultat de :"<<a<<"-"<<b<<" = "<<fonction(a, b, '-')<< endl;
cout<<" le resultat de :"<<a<<"*"<<b<<" = "<<fonction(a, b, '*')<< endl;
cout<<" le resultat de :"<<a<<"/"<<b<<" = "<<fonction(a, b, '/')<< endl;

return 0;
}