I can not understand this ?

Question

$a=2;
$b=$a++
Echo $b;

The answer is 2
How its does please describe

Answer 1

Its because your assigning the value of $a before its incremented by 1 try assigning ++$a if your expecting 3.

$a++ means use the value of $a and then incremenet by one

++$a means incremnet $a by 1 and use it

Answer 2

increment: ++, and decrement: --, operators.

• These operators can be placed before or after the variable expression they modify.
• If they are placed before (a prefix operator), they modify the variable expression before its value is used.
• If they are placed after (a postfix operator), they modify the variable expression after its value is used.

• The prefix and postfix increment both increase the value of a number by 1.

• The only difference between the two is their return value. The former increments (++) first, then returns the value of x, thus ++x. The latter returns the value of x first, then increments (++), thus x++.

Answer 3

https://www.sololearn.com/learn/5357/?ref=app

Answer 4

I've suffered a same type of confusion but in other language.
Hope it will help you and please use the search bar before posting any questions. Happy coding....
https://www.sololearn.com/discuss/1714986/?ref=app

Answer 5

Thank you all guys i got answer