Program on kaprekar number.

Question

A number say 45 when squared gives 2025, so 20+25 gives 45. But my program gives me "Time limit exceeded". Can somebody tell me what am i doing wrong. Learning python new.
https://code.sololearn.com/c2NTNAnpEFM8/?ref=app

Answer 1

The while loop is infinite. The condition n!=0 is always true because n never decreases.

Answer 2

Nice code Sagnik, where did you get the formula for unique number? the one I found online has different specification here:

http://www.guideforschool.com/203266-java-program-to-check-for-unique-number/

And why you check elif n%10 < 0? are you accepting negative numbers?

Answer 3

Sagnik no problem, good job you fix the problem. Can kaprekar number program accept negative input? please explain the elif n%10 < 0 because I don't understand ...

Answer 4

Sagnik Majumder2
Good job!
We can simplify it like this ...

n1 = count // 2
if count % 2 != 0:
n1 += 1

This way we don't need an else block at bottom ...

Please edit the forum question, so not confuse people, it still says "Program on unique number." 😁

Answer 5

Sagnik I made a mistake up there in code sample, but now it's fine, I changed it, just letting you know ... 👍

Answer 6

Thankx i have made the required changes😁

Answer 7

Sry my bad, its kaprekar number. Thanks 😅

Answer 8

Actually i am using the while loop to find the length of the number, so the if statement counts the number to till the last digit. I have used the elif statement to increase the count by 1 for the last(first) digit.

Answer 9

It seems my code dont work for numbers like 297

Answer 10

Yeah i removed that😊