How to execute this code it showing error Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 3 at detyra1.mai

Question

public static void main(String Args[]) {

int[] array = new int[3];
for (int i=0; i<4; i++)
{
array[i] = 5+i;
}
array[0] = 2/0;
for(int i=0; i<3;i++)
{
System.out.println(array);
}
System.out.println("Ekzekutimi nuk do te arrin deri ketu");

}

}

Answer 1

1. The first loop limit was not within the range of array bounds (index 0 ~ 2), change this line:
for(int i = 0; i < 4; i++)
into
for(int i = 0; i < 3; i++)

2. You are dividing by zero at this line, I don't know what you want so I can't suggest anything but just don't divide number with zero.
array[0] = 2 / 0;

3. In your second loop, you are printing the array without any index reference, so you get raw string representation of the array. Change this line:
System.out.println(array);
into
System.out.println(array[i]);

Make the fix and let me know how it goes.

Answer 2

Becz your array only stores 3 value And you are trying to add four values.

So Change value 3 to 4.

Answer 3

Good job! 👍

Answer 4

thank you it works

Answer 5

it showing error /by zero