ASYNC JS: ES6 Promise.all method - unexpected output dilemma.

Question

My question is about why there are two expected outputs from sololearn challenges in this chunk of ajax code but when I test in the debugger this gives me only [foo, car] as output?

const a = new Promise((res, rej) => { //n1
    setTimeout(() => res('foo'), 300);
});

const b = new Promise((res, rej) =>  {
    setInterval(() => rej('bar'), 100);
    res('car');
});

Promise.all([a, b]).then((race) => {
    console.log(race);
}).catch((crash) => {
    console.log(crash);
});

Right answers:
[foo, car]
['bar', 'car']
- why this?

Answer 1

I have not much idea about js promises but i can help you with this link..

https://stackoverflow.com/questions/55979096/ajax-promise-all-method-unexpected-output-dilemma

Answer 2

DPP

Please donot spam.
https://www.sololearn.com/discuss/1316935/?ref=app