Numpy dot multiplying

Question

I tried numpy dot in a neural network design

#code that fails
import numpy as np

def sig(x,d=False):
if d:
return 2*(1-x)
return 1/(1+np.exp(-x))

inps=np.array([[0,0],
[0,1],
[1,0],
[1,1]])
exout=np.array([[0],[1],[1],[1]])

np.random.seed(1)
w0=2*np.random.random((2,4))-1
w1=2*np.random.random((4,1))-1

numberofexecutions=100000

for i in range(numberofexecutions):
l0=inps
l1=sig(np.dot(l0,w0))
l2=sig(np.dot(l1,w1))
l2e=exout-l2
l2d=l2e*sig(l2,d=True)
l1e=l2d.dot(w1.T)
l1d=l1e*sig(l1,d=True)
w1+=l1.T.dot(l2d)
w0+=l0.T.dot(l1d)
#print(l2)
ab=int(input())
bc=int(input())
ac=np.array([ab,bc])
l1a=sig(np.dot(ac,w0))
l2a=sig(np.dot(l1a,w1))
l3a=sig(np.dot(l2a,w2))
print(overflo(l3a))

#code that works
import numpy as np

def sig(x,d=False):
if d:
return 2*(1-x)
return 1/(1+np.exp(-x))

inps=np.array([[0,0],
[0,1],
[1,0],
[1,1]])
exout=np.array([[0],[1],[1],[1]])

np.random.seed(1)
w0=2*np.random.random((2,4))-1
w1=2*np.random.random((4,1))-1

numberofexecutions=100000

for i in range(numberofexecutions):
l0=inps
l1=sig(np.dot(l0,w0))
l2=sig(np.dot(l1,w1))
l2e=exout-l2
l2d=l2e*sig(l2,d=True)
l1e=l2d.dot(w1.T)
l1d=l1e*sig(l1,d=True)
w1+=l1.T.dot(l2d)
w0+=l0.T.dot(l1d)
print(l2)

Answer 1

found awnser

Answer 2

I dont see an issue, but I am new to neural networks.