Why it doesn't gives output of more than 8*a for any no.?pls need help

Question

printing table

https://code.sololearn.com/cUen5vODgwQH/?ref=app

Answer 1

In void display () for loop needs to go to n, not a.

You ask user to input number cin>> n but you are not using it anywhere.

Answer 2

Your multiplication method is off. It's not logical to me. You just can't use a and n without having some if statement to check the input value of n. Even then, you'll have to check the value as well in display method.

Number 8 is a random number in the memory. It could be any number really.

Answer 3

dρlυѕρlυѕ ,no problems now ,I removed that second function which I thought isn't really necessary ,works as I wanted

Answer 4

dρlυѕρlυѕ cout<<"table is as follow"<<n<<"*"<<i<<"="<<n*i;

Answer 5

dρlυѕρlυѕ ,why doesn't this Loop runs to 10 for a ,while it works perfectly for n?

Answer 6

dρlυѕρlυѕ , thks but this is weird why does it takes 8 as value for any value passed to a variable?

Answer 7

dρlυѕρlυѕ Why it's a simple program where it takes the default argument value and prints the table for it upto the no. user inputs?

Answer 8

dρlυѕρlυѕ it assigns 5 to a ,so why 8 then?