Initializing byte variables with hex numbers in Java

Question

I am trying to initialize or assign a hex number to a byte variable. Whenever I do:
byte c = 0xFF;
Compiler throws an error.
But when I do:
byte c = 0xFFFFFFFF;
Compiler doesn't throw an error.
I think it is related to the int s which are 32 bits. Could you tell it why it is so?

Answer 1

byte is signed, possible values are from
Byte.MAX_VALUE == 127
Byte.MIN_VALUE == -128

literal numbers are processed as signed integer
0xFF is 255 and is not accepted
0xFFFFFFFF is -1 and is accepted to assigned to byte type

byte c =0xFFFFFFFF;
System.out.println(c); // -1

(byte) 0xff // -1
int i = Byte.toUnsignedInt( (byte) 0xFF ); //255

Byte.SIZE; //8
Byte.BYTES; // 1