Why the below code is showing the value of x as 16 however it should be 1 similar to the y. Please help me.

Question

#include <stdio.h>
#define sqr(x) x*x

int main() {
int x = 16/sqr(4);
int y = 16/16;
printf("%d\n",sqr(4));
printf("x=%d\n",x);
printf("y=%d\n",y);
return 0;
}

Answer 1

x == 16/sqr(4) == 16/4*4 == 16.
y == 16/16 == 1.
z == 16/(sqr(4)) == 16/(4*4) == 1.