Is there an any way to create dictionary by range like this ?

Question

try:
a = tuple (range (3))
print (a)

b = list (range (3))
print (b)

c = set (range (3))
print (c)

d = dict (range (3))
print (d)

except:
print ("dict error")
_____________________
output:

(1,2,3)

[1,2,3]

{1,2,3}

dict error

Answer 1

Unlike tuples, lists, and sets, dictionaries require a key-value pair for each entry. However, if you want all of your elements in the range to be keys with the SAME value, say, 42, then you can try this:

d = dict.fromkeys(range(5), 42)

But I think the dictionary comprehension as suggested by Jay is much cleaner and far more versatile.

Answer 2

d = dict(zip(range(3), 'abc'))

Answer 3

I am a little bit late with my comment. Coming back to Annas code you can slightly modify it, if you have already a list for the values:

lst = ['xp', 'w3', 'ib']
d1 = dict(zip(range(3), lst))
print(d1)

# result: {0: 'xp', 1: 'w3', 2: 'ib'}

Answer 4

thanks 🙏 all!!)