js problem for loop

Question

what is going on in this code explain me plz!
for( var i=0; i<=8; i++){
i+=i
console.log(i)
}
why result is 0 2 6 14

Answer 1

i+=i => i+i, so the first number in the loop 0 +0 =0; the second 1+1=2; the third 3+3=6; the fourth 7+7=14; then the loop will stop cause the condition will be false that equal or less than 8;

Answer 2

i += i is the short way of saying i = i + i (or, basically, multiply i by 2).

First iteration: i = 0
i + i =0
Increase i by 1

Second iteration: i = 1
i + i = 2
Increase i by 1

Third iteration: i = 3
i + i = 6
Increase i by 1

Fourth: i = 7
i + i = 14

Stops because i is now greater than 8.

Answer 3

~~ if you already know how loops work, skip this part ~~

First, the base, i = 0.
Then you give a little if-statement for the increment/last part. i <=8 when i is smaller then or equal to 8, do the loop
Lastly, the increment. i++ is used here. First it uses i, then it increments i (after the loop) if you loop (i=0; i<5; i++) you get 0 1 2 3 4, if you use (i=0; i<5; ++i) you get 1 2 3 4

Now that we know that, let's move to what's inside the loop

~~ end of the loop part, continue from here if you skipped ~~

Now inside the loop are two things, an increment of i (i+=i which is the same as i=i+i or i=2*i)
So it doubles i and then it prints i in the console.

Now for the loop it goes like this
i=0 (first time) i+=i; i=0+0; i=0
console.log( 0 )
i++ (from the loop) i=1
i=1 (second) i+=i; i=1+1; i=2
console.log( 2 )
i++ (from the loop) i=3
i=3 (3th) i+=i; i=3+3; i=6
console.log( 6 )
i++ (from the loop) i=7
i=7; (4th and last) i=7+7; i=14
console.log( 14 )
i <= 8 is no longer true, therefor end output=(0 2 6 14)