print(range(x)) flaw

Question

print(range(X))

Output : range(0,X)

Why ?

Answer 1

range(start, stop, step) creates a range object that goes from <start> to <stop-1> in steps of <step>. If you omit <start> and <stop>, Python assumes that <start> is 0 and <step> is 1. So range(5) is exactly the same as range(0, 5) or range(0, 5, 1). I don't see any flaw.

Answer 2

You can fix it like this:

print(list(range(X)))

This will make a list out of it, so it won't just output the function

Answer 3

Yes, I read it works this way but what's the flaw in that ? How it works behind the scenes ?

Answer 4

It's because in python3 you have to make it a list

Answer 5

It works using __iter__. I think range isn't a function, but a class.

Let try to create it.
class range:

def __init__(self, start, stop) :
self.start = start
self.stop = stop
self.actual = self.start - 1

def __iter__(self) :
return self

def __next__(self):
self.actual += 1
if self.actual < self.stop:
return self.actual
else:
raise StopIteration()

def __repr__(self):
return "range(0, X)"

Answer 6

A good explanation is that range really doesn't create a list but it is a lazy promise to produce that values as and when required