boolean and operator precedence

Question

i understand the answer of this program is "no" please can someone help me break it down
What is the result of this code?
x = 4
y = 2
if not 1 + 1 == y or x == 4 and 7 == 8: #i am more confused here, as there are or and and
print("Yes")
elif x > y:
print("No")

Answer 1

not 1 + 1 == y or x == 4 and 7 == 8
Let's change the variable names to their values to increase readability:
not 1 + 1 == 2 or 4 == 4 and 7 == 8

Arithmetic operators are performed first:
1 + 1 = 2
not 2 == 2 or 4 == 4 and 7 == 8

Comparison operators are performed second:
2 == 2 = True
4 == 4 = True
7 == 8 = False
not True or True and False

Now there are only logical operators left.
Comparison operators also have an operator precedence: not: first, and: second, or: third.

First let's get not True:
not True = False
False or True and False

Then let's get True and False:
True and False = False
False or False

Then let's get False or False and we'll have the final result:
False or False = False

final result:
False