Linked List in C

Question

Im trying to create Linked list in c language and I have this unexpected result when I'm trying to add an element at the beginning of the List.
Can you find my mistake?
Here is my code:
https://code.sololearn.com/c62w8vcJnb8R/?ref=app

Answer 1

David Carroll check out the number of comments in Gordie [#observer_status_only] 's code. I suppose they have a place in explaining code to someone who needs more understanding? What do you think?

Answer 2

Sonic The use of code comments in code used for instructional purposes or for a learner to preserve their thoughts is 100% appropriate. 😉👌

Answer 3

If you use 1 * you create a copy of the pointer. If you make it point somewhere else in the function, which you are doing here, it is not reflected outside the function.
The 1st * is there for the type itself (node_t*) and the 2nd * is there for the address of the pointer.

So no, it's either ** and & or * and return the head.

Answer 4

SPush(head, 14); should be SPush(&head, 14);
Some people choose to return the head so you can avoid the & and the **.

Answer 5

Yea, that's what pointers do to you.
Try not to overthink it.
It's just an integer that uses different CPU instructions.
You'll get the hang of it if you use it alot. :)

Answer 6

Can I simply change the ** to * and avoid the &, will be the save work done?

Answer 7

It's a little bit tricky to my mind...

Answer 8

I'm trying to understand them by writing every variable and every pointer on a paper and it's value and the variable it is pointing to.