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Help !!!!
The parametric equations of a curve are x = 1 +tan θ , y=sec θ , for -1/2pi < θ < 1/2 pi Show that dy/dx = sin θ Find the coordinates of the point on the curve ar which the gradient of the curve is 1/2
4 odpowiedzi
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Prometheus 🇸🇬 you helped and scolded.... 😂😂
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This is a coding app not Math StackExchange.
Please keep your questions programming oriented on this site.
https://www.sololearn.com/discuss/1316935/?ref=app
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dy/dx=(dy/dθ)/(dx/dθ)
=sec^2(θ)/(sec(θ)tan(θ))
=secθ/tanθ
=sinθ
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great answer 👍👏👏 Prometheus 🇸🇬