May i know what is the parameter separated by comma in that definition. actually i'm confused whether it is the actual argument

Question

def my_func(f, arg):
return f(arg)

my_func(lambda x: 2*x*x, 5)

Answer 1

Hi.

There are quite some cool features nested.
The lamba as a definition in place. This given to a function that does nothing more than taking the reference to a function and filling in the argument to the call and returning the result (I am guessing 50?)

Hope that helps. Cheers. C