Write a python program to find Hardy Ramanujan number

Answer 1

def sai(a):
c=0
for i in range(1,2000):
for j in range(1,2000):
if (j*j*j)+(i*i*i)==a:
c=c+1
if c==2:
return "yes"
break
else:
return "no"

a=int(input())
b=sai(a)
print(b)

Answer 2

The obvious and dirty way (only positive values):

def dirty_hdn():
for x in range(1, 2000):
for y in range(1, 2000):
for z in range(1, 2000):
for g in range(1, 2000):
if g * g * g + z * z * z == x * x * x + y * y * y:
if (g == z)|(g == y)|(g == x)|(z == y)|(z == x)|(y == x):
continue
else:
print ("x=", x)
print ("y=", y)
print ("z=", z)
print ("g=", g)
print (g * g * g + z *z* z)
return "Taxidriver"