Why does it output 3 1 4 2 and not 1 2 3 4 ?

Question

https://code.sololearn.com/cEU52VbjTvrp/?ref=app

Answer 1

Vincent Maestro shouldn't be, just understand that you always get your pop up results in stack in reverse order compared to your pushing from input

Answer 2

Stack is last input first output, so it is like you fill one railway with wagons and start to remove wagons from the end

Answer 3

Vincent Maestro so you have to get them in reverse order, so everything is correct

Answer 4

Vincent Maestro sorry first in last out, sorry i confused it with queue

Answer 5

A stack is first in last out.
So the first value 1 comes out as the last value after 3.

A queue is first in first out.

Answer 6

I don't get your question. Your code works fine, you just have to think about it.

stack1.push(1);
stack2.push(2);
stack1.push(3);
stack2.push(4);

If you think about it, the first stack contains [1, 3], and the second stack contains [2, 4]. If you pop stack1, then stack2, you should and will get [3, 1, 4, 2]

Answer 7

Zhenis Otarbay first input, first output right?

Stack1 recieved (1) before it received (3) similarly Stack2 received (2) before receiving (4) so why does pop return 3 before 1 and 4 before 2 ?

Answer 8

Airree I believe 1 was stored before 3 and 2 before 4 so why does the output go 3 1 4 2 ?
That's just a little confusing to me

Answer 9

Any line of code doing some manipulation I don't know about?