How to check if the input matches one of the lucky number and print it? Using python

Question

select=input("please enter your lucky number: ")

Luck_number=[1,2,3,4,5,6,7,8,9]

if(select==Luck_number[]):
print("Congratulations you are the winner")
else print("Sorry you did not win! Please try again")
end if

Answer 1

You can do it like this with the in operator:

if select in Luck_number:

(Also, oooking at your code, you got QUITE a few things wrong.
- The input needs to be converted into an integer:
select = int(input())
- You don't need the parentheses for the if clause
- In python, indentation is VERY important. You can't just do
else print(...)
you have to do:
else:
print(...)
- Also you don't need "end if"
Try to keep things clean, Ok?)

Answer 2

Thank you for your help. I did figure it out as you gave the instruction.

Answer 3

You can also:-
select = int(input("please enter your lucky number: "))
Luck_number=[1,2,3,4,5,6,7,8,9]
print("You winner" if select in Luck_number else "You loose! Please try again")
# or
print("You winner") if select in Luck_number else print("You loose! Please try again")