+ 1
Can someone explain the output
#include<stdio.h> int main() { int a; char *x; x = (char *) &a; a = 512; x[0] = 1; x[1] = 2; printf("%dn",a); return 0; }
1 Odpowiedź
#include<stdio.h> int main() { int a; char *x; x = (char *) &a; a = 512; x[0] = 1; x[1] = 2; printf("%dn",a); return 0; }