Can anyone explain how the and statement is not included in output

Question

#include <stdio.h>

int main() {
int i=4, j=7;
j = j || i++ && printf("you can");
printf("%d %d", i, j);
return 0;
}
Please explain the whole code

Answer 1

The || operator checks for true values. If the first value is true, then it won't bother checking the other side, so the whole && thingy will have been left out.

Answer 2

But as and operator has higher precedence then why that is not evaluate at first

OR this is an exception in logical operators