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3 out of 4 Boolean Check
Can someone give me an example of how to check if 3 out of 4 Boolean variables are valid? This is what I tried but didnt work: if ((a?1:0) + (b?1:0) + (c?1:0) + (d?1:0) >= 3)
4 odpowiedzi
+ 3
var a = true;
var b = true;
var c = false;
var d = true;
if(a + b + c + d == 3){
console.log("is 3");
}else{
console.log("not 3");
}
+ 2
Jacques Cozart
I see some logical error here, one is that you should be using '==' operator instead of '>=' operator as you are looking for exactly 3 true values.
second error is not understanding precedence and associativity of operators, whenever you are unsure of it, you can make use of brackets()
//not sure whether 1+2*3 will be taken as (1+2)*3 or 1+(2*3)
if (((a?1:0)+(b?1:0)+(c?1:0)+(d?1:0))==3)
console.log("is 3");
else console.log("not 3");
//I am also not sure of these in javascript so I used () to remove if any such error
+ 1
Thanks, I will test it out!
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So an applcant needs to have at least 3 of the 4 skills. Here is what I have and still get the wrong output. It accepts the word skill, but then puts the next three skill questions in a line with a 0 at the end?......
public static void Boolean ApllicantSkills(Boolean word, Boolean spreadSht, Boolean dataBase, Boolean graph)
{
Boolean applicantSkills =true;
if(((word?1:0) + (spreadSht?1:0) + (dataBase?1:0) + (graph?1:0)) ==3)
System.out.println(“Qualified”);
else
System.out.println(“Not Qualified”);
return applicantSkills;
}}