square root without math.h

Question

Hi, i'm making an algorithm which give the square root of a number.
The problem is that it gime te square root but with a decimal extra.
Example: the square root of 4, 2.1.

#include <iostream>

using namespace std;

int main()

{

float n1,i=0,res;

cout<<"Digite un numero para hallar su raíz cuadrada: ";

cin>>n1;

do{

//Many decimals for more precision.

i=i+0.00001;

res=i*i;

}

while(res<=n1);

cout<<endl<<"La raíz cuadrada es: "<<i;

return 0;

}

Answer 1

You can typecast i to integer. That way decimal will be removed.

cout << (int)i << endl;

Answer 2

Look for Newton-Raphson if you need a more effective approach to determine a square root.