Delete a word next to another one(python)

Question

i need to do the capslock part of this code

list1["red","one"]

import random

#input
input1=input("min 3 words").split()
print(" ")

if ("dei")in input1:
input1.remove(#REMOVE THE WORD NEXT TO DEI)
text=" ".join(input1)
print(text, random.choice(list1))

Answer 1

if i get your request right you want this:

if "dei"in input1:
input1.remove(input1[input1.index("dei")+1])
text=" ".join(input1)
print(text, random.choice(list1))

with the list.index() function you call the index of 'dei' and then you can go one further by adding 1 to the index. Plugging that index to the list to get the word which than can be removed.

Answer 2

def removeNext(str1, str2):
rtn = ""
skips = 0
toSkip = False
for word in str1.split():
if(toSkip):
toSkip = False
continue
if(word == str2):
if(skips == 0):
toSkip = True
skips = 1
rtn = rtn + word + " "
else:
rtn = rtn + word + " "

return rtn[:-1]

a = "de dei di"
if("dei" in a.split()):
input1 = removeNext(a, "dei")